+0  
 
0
127
2
avatar+2291 

All help is greatly appreciated :D

RainbowPanda  Aug 10, 2018
 #1
avatar+92787 
+2

First of all...the cable car's  avg rate of change is constant....it is  straight line

It changes  by 50 ft per second  over all the given intervals

 

Pat's rate of change  from 0 to 2

[ 125 - 0 ] / [ 2 - 0 ]  =  125 / 2  =  62.5 ft /min

 

From 2 to 4

[ 200 - 125 ] / [ 4 - 2 ] =  75/2  = 37.5 ft / min

 

From 4 to 5

[ 225 - 200] / { 5 - 4 ]  =  25 /1  =  25 ft / min

 

Looks like Pat is running out of gas at the end while the cable car maintains the same steady pace.....LOL!!!

 

b Pat's rate of change is not constant.....the cable car's rate of change is

 

c Pat's average rate over the ntire trip  =  [ 250 - 0 ] / [ 6 - 0 ] = 250 / 6 ≈ 41.66 ft / min

As before....the cable car's rate  =  50ft / min

 

 

 

cool cool cool

CPhill  Aug 10, 2018
 #2
avatar+2291 
+1

Tysm for all of your help! I'm guessing you want me to do the cable cars avg rate of change for 5a

RainbowPanda  Aug 10, 2018

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