All the natural numbers from 1 to 100 are placed in a hat. Two are drawn at random without replacement. What is the probability of getting 2 numbers containing the digit 9 in the ones place?

Guest Apr 16, 2020

#1**+1 **

The numbers with a digit of 9 in the one's place are: 9, 19, 29, 39, 49, 59, 69, 79, 89, and 99.

The probability of getting the first number with a 9 in the one's place is 10/100.

The probability of getting the second number (without replacement) with a 9 in the one's place is 9/99.

To find the final probability, multiply these numbers together: 10/100 x 9/99 = ...

geno3141 Apr 16, 2020