Altitudes AD and BE of triangle ABC intersect at H. If angle BAC=54 and angle ABC=62, then what is angle AHB?
B
62
D
H
A 54 E C
Angle ADB = 90
Angle BAD = Angle BAH = 90 - 62 = 28
Angle DAE = Angle HAE = 54 - 28 = 26
Angle AEB = Angle AEH = 90
So angle AHE = 90 - 26 = 64
So angle AHB = 180 - 64 = 116°
