The air in a car's tire is at a pressure of 240 kPa and a temperature of 290 K. After the car is driven, the temperature of the air has risen to 320 K. What is the new pressure of the air in the tire?
I believe this is correct:
240kPa / 290K = ? / 320K multiply both sides by 320K
[320K / 290K] * 240kPa ≈ 264.83kPa
