An airplane flying into a headwind travels the 1650-mile flying distance between two cities in 3 hours and 18 minutes.
On the return flight, the distance is traveled in 3 hours.
Find the airspeed of the plane and the speed of the wind, assuming that both remain constant.
An airplane flying into a headwind travels the 1650-mile flying distance between two cities in 3 hours and 18 minutes.
On the return flight, the distance is traveled in 3 hours.
Find the airspeed of the plane and the speed of the wind, assuming that both remain constant.
3hours and 18 minutes is 3.3 hours
outward flight speed = 1650/3.3 = 500 miles / hour
return speed = 1650/3=550 miles /hour
let p be the plane speed and let w be the wind speed
p + w = 550
p - w = 500
2p = 1050
p = 525
2w = 50
w = 25
The wind speed is 25 miles/hour and the planes speed is 525 miles /hour