An airplane flying into a headwind travels the 1650-mile flying distance between two cities in 3 hours and 18 minutes. On the return flight, the

An airplane flying into a headwind travels the 1650-mile flying distance between two cities in 3 hours and 18 minutes. 
On the return flight, the distance is traveled in 3 hours. 
Find the airspeed of the plane and the speed of the wind, assuming that both remain constant.

 

3hours and 18 minutes is  3.3 hours

outward flight speed = 1650/3.3 = 500 miles / hour

 

return speed = 1650/3=550 miles /hour

 

let p be the plane speed and let w be the wind speed

 

p + w = 550

p - w = 500

 

2p = 1050

p = 525

 

2w = 50

w = 25

 

The wind speed is 25 miles/hour  and   the planes speed is  525 miles /hour