+0  
 
0
779
4
avatar+1904 

\(5^(x-\sqrt(2))=25\); Solve for x.

 Dec 18, 2015
 #1
avatar
0

Solve for x:
5 (x-sqrt(2)) = 25

Divide both sides of 5 (x-sqrt(2)) = 25 by 5:
(5 (x-sqrt(2)))/(5) = 25/5

5/5 = 1:
x-sqrt(2) = 25/5

The gcd of 25 and 5 is 5, so 25/5 = (5×5)/(5×1) = 5/5×5 = 5:

 x-sqrt(2) = 5
Answer: | x=5 + sqrt(2)
 

 Dec 18, 2015
 #2
avatar+1904 
0

Actually the equation is not 5 (x-sqrt(2)) = 25, but is 5^(x-sqrt(2)) = 25,  Your answer is wrong.

 Dec 18, 2015
 #3
avatar
+5

Thanks to your goofing!: Here is your new answer, smart Aleck!.

 

Solve for x over the real numbers:
5^(x-sqrt(2)) = 25

Take the logarithm base 5 of both sides:
x-sqrt(2) = 2

Add sqrt(2) to both sides:
Answer: |  x = 2+sqrt(2)
 

 Dec 18, 2015
 #4
avatar+8581 
0

Wow, Savage.

 Dec 18, 2015

3 Online Users

avatar
avatar