+64 An automobile radiator holds 6 liters of liquid and is full of a liquid which is 30% antifreeze. How many liters of this liquid should be replaced by pure antifreeze in order to obtain a mixture which is 50% antifreeze?
An automobile radiator holds 6 liters of liquid and is full of a liquid which is 30% antifreeze. How many liters of this liquid should be replaced by pure antifreeze in order to obtain a mixture which is 50% antifreeze?
50% of 6 =3 liters
30% x 6 =1.8 liters is antifreeze.
3 - 1.8 =1.2 liters should be replaced to get 3 liters or 50% of antifreeze, because:
1.8 + 1.2 = 3 Liters of antifreeze, which is 50% of 6 liters of liquid that the radiator holds.
