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# An integer greater than 9 and less than 100 is randomly chosen. What is the probability that its digits are different?

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An integer greater than 9 and less than 100 is randomly chosen. What is the probability that its digits are different?

Darkside  Sep 2, 2018
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From the $$10$$ to $$99$$, there are $$90$$ numbers. Out of these numbers, $$9$$ have the same digits($$11, 22, 33, 44, 55, 66, 77, 88, 99$$). So your probability would be $$\frac{81}{90} = \frac{9}{10}$$

- Daisy

dierdurst  Sep 2, 2018