We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
+1
205
1
avatar+294 

An integer greater than 9 and less than 100 is randomly chosen. What is the probability that its digits are different?

 Sep 2, 2018
 #1
avatar+391 
+2

From the \(10\) to \(99\), there are \(90\) numbers. Out of these numbers, \(9\) have the same digits(\(11, 22, 33, 44, 55, 66, 77, 88, 99\)). So your probability would be \(\frac{81}{90} = \frac{9}{10}\)

 

- Daisy

 Sep 2, 2018

7 Online Users

avatar
avatar
avatar