An investment fund has increased in value by a total of 21% over the last 2 years.urgent

Great..Thank you :*

Urgently!Please!Its N emergency 

It is worth $1210 now    the interest earned is $210

Simple interest

I = Prt

210 = 1000(r)2

210 = 2000 (r)

r = .105 = 10.5% = simple interest rate

Compound Interest

1210 = 1000(1+ r)²    Divide both sides by 1000

1.21 = (1 + r)²           Take the log of both sides

log 1.21 = log (1 + r)²    By a property of logs, we have

log 1.21 = 2 log (1 + r)    divide by 2 on each side

(log 1.21) / 2 = log (1 + r)

.041392685158225 = log (1 + r)

So we have

10^{.041392685158225}  = r + 1

1.099999999999999897 = r + 1   subtract 1 from both sides

r = .0999999 =  9.99999% = 10% = compound interest rate

Please solve it without using log function 

OK...so we have

1000(1 + r)(1 +r) = 1210      divide by 1000

(1 + r)²    = 1.21      take the square root of both sides

1 + r = 1.1               subtract 1 from both sides

r = .1  = .10 = 10%

How's that??

Thank you anonymous for you good manners.