An object of weight 7.5N hangs on the end of a cord, which is attached to the midpoint of a wire stretched between two points on the same horizontal level. each half of the wire is at 12° to the horizontal. calculate the tension in each half of the wire.
+37084 Sum of vertical forces in the wires must equal the downward force of 7.5 N
2t sin 12 = 7.5 '2' because there are 2 wires t = tension and 12 degrees is the angle given
t= 7.5/(2sin12) = 18.04 N
