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Points $A(0, 0)$, $B(6, 0)$, $C(6, 10)$ and $D(0, 10)$ are vertices of rectangle $ABCD$, and $E$ is on segment $CD$ at $(2, 10)$. What is the ratio of the area of triangle $ADE$ to the area of quadrilateral $ABCE$? Express your answer as a common fraction.

 Feb 25, 2021
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$\triangle ADE$ has base $2$ and height $10$, so it has area $10$. The area of the rectangle is $6*10=60$, so the answer is $\frac{10}{60-10}=\frac{10}{50}=\boxed{\frac15}$.

 

From MATHCOUNTS? (only source that asks for common fraction, unless it's illegal AoPS homework)

 Feb 25, 2021

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