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A circle passes through the point (12,0), and is tangent to the y-axis at the point (0,8). Find the radius of the circle.

 Mar 17, 2021
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I believe the center of the circle has to be equidistant to (12, 0) and (0, 8). 

So the raduis could be any length greater than 5sqrt(2). 

But I'm probably missing something. 

Sorry I couldn't help more. :))

 

 

=^._.^=

 Mar 17, 2021

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