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# Analytic geometry

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A circle passes through the point (12,0), and is tangent to the y-axis at the point (0,8). Find the radius of the circle.

Jul 16, 2022

#1
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Because the circle is tangent to the y-axis at $$(0,8)$$ tells you that the y-coordinate of the center is 8.

Now, recall that any 2 points that lie on the circle must be equidistant to the center. Use the distance formula, set them equal, and substitute $$y = 8$$

Can you take it from here?

Jul 16, 2022
#2
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BuilderBoi, do you like to take it up the $$\text{a} \text{s} \text{s}$$?

Guest Jul 16, 2022