A circle passes through the point (12,0), and is tangent to the y-axis at the point (0,8). Find the radius of the circle.

Guest Jul 16, 2022

#1**0 **

Because the circle is tangent to the y-axis at \((0,8)\) tells you that the y-coordinate of the center is 8.

Now, recall that any 2 points that lie on the circle must be equidistant to the center. Use the distance formula, set them equal, and substitute \(y = 8\)

Can you take it from here?

BuilderBoi Jul 16, 2022