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A circle passes through the point (12,0), and is tangent to the y-axis at the point (0,8). Find the radius of the circle.

 Jul 16, 2022
 #1
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Because the circle is tangent to the y-axis at \((0,8)\) tells you that the y-coordinate of the center is 8. 

 

Now, recall that any 2 points that lie on the circle must be equidistant to the center. Use the distance formula, set them equal, and substitute \(y = 8\)

 

Can you take it from here?

 Jul 16, 2022
 #2
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BuilderBoi, do you like to take it up the \(\text{a} \text{s} \text{s}\)?

Guest Jul 16, 2022

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