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Please help quick.
1.

2.

3.

 Feb 23, 2024
 #1
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1. -4/3, I just graphed it in desmos and fiddled with some stuff.

 

2. So the distance of the Center, (x,y), to B and A are the same.

 

We know that y is 5 from tangent rules.

 

(x,5)

The distance from (x,5) to (9,0) is x, since to B is also x

\(\sqrt{(9-x)^2+25}=x\)

\((9-x)^2+25=x^2\)

\(x^2-18x+106=x^2\)

\(x = \frac{53}{9}\)

\((53/9,5)\)

 Feb 23, 2024

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