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A billiard ball is struck by a cue. It travels 150cm before ricocheting off a rail and
traveling another 200cm into a corner pocket. The angle between the path as the ball
approaches the rail and the path after it strikes the rail is 60 . How far is the corner
pocket from where the cue initially struck the ball? Round your final answer to 4
decimal places.

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 Nov 13, 2018
 #1
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Using Law of Cosines

 

c^2 = a^2 + b^2 - 2 a b cos c

 

c^2 = 150^2 + 200^2 - 2(150)(200)cos 60   = ====   c = 180.2776 cm

 Nov 13, 2018
edited by ElectricPavlov  Nov 13, 2018

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