A billiard ball is struck by a cue. It travels 150cm before ricocheting off a rail and

traveling another 200cm into a corner pocket. The angle between the path as the ball

approaches the rail and the path after it strikes the rail is 60 . How far is the corner

pocket from where the cue initially struck the ball? Round your final answer to 4

decimal places.

marlina96 Nov 13, 2018

#1**+1 **

Using Law of Cosines

c^2 = a^2 + b^2 - 2 a b cos c

c^2 = 150^2 + 200^2 - 2(150)(200)cos 60 = ==== c = 180.2776 cm

ElectricPavlov Nov 13, 2018