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Let $\overline{AB}$ be a diameter of a circle, and let $C$ be a point on the circle such that $AC = 4$ and $BC = 4.$ The angle bisector of $\angle ACB$ intersects the circle at point $M.$ Find $CM.$

 Mar 19, 2024

Best Answer 

 #1
avatar+15069 
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¯CM=¯AB=42+42=32=5.65685

 

laugh  !

.
 Mar 20, 2024
 #1
avatar+15069 
+1
Best Answer

¯CM=¯AB=42+42=32=5.65685

 

laugh  !

asinus Mar 20, 2024

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