In triangle $ABC,$ let the angle bisectors be $\overline{BY}$ and $\overline{CZ}$. Given $AB = 14$, $AY = 14$, and $CY = 8$, find $BC$.
A
14
14 Y
8
B C
Since BY is an angle bisector
AB / AY = BC / CY
14 / 14 = BC/ 8
BC = 8
+1418 
