+36916 Angle bisector theorem
56/xb = 14/ax note that xb = 50 -ax sub that in
56 / (50 - ax) = 14/ax
56 ax = 14 (50 - ax)
70 ax = 700
ax = 10
+36916 Angle bisector theorem
56/xb = 14/ax note that xb = 50 -ax sub that in
56 / (50 - ax) = 14/ax
56 ax = 14 (50 - ax)
70 ax = 700
ax = 10
