In triangle ABC, angle bisectors AD,CF and BE meet at I. If DI=3, BD=3, and BI=6, then compute the area of triangle ABC.
This is impossible
Look at triangle BDI
BD = 3 DI = 3 and BI = 6
By the triangle inequality theorem, BD + DI must be greater than BI
But
BD + DI = BI
So......this inner triangle cannot exist
It can, calculus
