The angle of elevation from a viewer to the top of a flagpole is 50˚. The viewer is 40 ft away and the viewer’s eyes are 5.5 ft from the ground. How high is the pole to the nearest tenth of a foot?

Call the distance on the flagpole 5.5 feet above the ground to the top X.

tan(50^{o}) = X/40 ---> X = 40 · tan(50^{o})

Find this value, add the 5.5 feet, and round your answer.