Two lines p and q intersect at X at an angle of 39 degrees. Let A be a point inside the 39 degree angle formed by p and q. Let B be the reflection of A through line p, and let C be the reflection of A through line q. Find angle BAC, in degrees.
I don't even know where to start. Could I have a nudge in the right direction please?
Since A is reflected over p to B.....let the point of reflection on p be = M
So angle AMX = 90°
Likewise......since A is reflected over q to C....let the point of reflection on q = N
And angle ANX = 90°
So angle BAC will = angle MAN
BAC = 360 - angle BXC - angle AMX - angle ANX = 360 - 39 - 90 - 90 = 141°