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Two lines p and q intersect at X at an angle of 39 degrees. Let A be a point inside the 39 degree angle formed by p and q. Let B be the reflection of A through line p, and let C be the reflection of A through line q. Find angle BAC, in degrees. 

I don't even know where to start. Could I have a nudge in the right direction please?

 Feb 20, 2021
 #1
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I think it might be 141, but I am not completely sure.

 Feb 20, 2021
 #2
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Since  A  is reflected  over p  to B.....let the point of reflection on p  be = M

So angle AMX  = 90°

Likewise......since A  is reflected  over q  to  C....let  the point of reflection on q =  N

And angle  ANX  =  90°

 

So   angle  BAC  will =  angle  MAN

 

So

 

BAC  =  360 -  angle BXC - angle AMX  - angle  ANX  =   360 - 39 - 90 - 90   = 141°

 

 

cool cool cool

 Feb 20, 2021
 #3
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Wow I never thought of doing it that way! Thanks CPhill!smiley 

Guest Feb 20, 2021

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