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There are people who think the earth is flat and that the sun orbits the earth at 3000 miles. If the sun is over the equator and I'm 2000 miles, at what angle would I see the sun?

The adjacent would be 2000, the opposite 3000. so it would be, o/a, then use the inverse of tan. Is this correct?

If so, I can use this procedure for any distance value for the adjacent?

Guest Jun 13, 2017

edited by
Guest
Jun 13, 2017

edited by Guest Jun 13, 2017

edited by Guest Jun 13, 2017

edited by Guest Jun 13, 2017

edited by Guest Jun 15, 2017

edited by Guest Jun 13, 2017

edited by Guest Jun 13, 2017

edited by Guest Jun 13, 2017

edited by Guest Jun 15, 2017

#1**+1 **

Actually, because of the Earth's curvature - and other factors - the procedure is a little more complicated.

You can read about it here :

http://www.pveducation.org/pvcdrom/properties-of-sunlight/elevation-angle

CPhill Jun 13, 2017

#3**+2 **

HAHAHA!!.....yeah...if you're amongst the "Flat Earthers"....then your procedure is "valid"....

CPhill Jun 13, 2017

#4**+1 **

No, flat earth theory makes no sense...:)...and thank you! I think one of the things that makes no sense is one person in particular thinks that a sun orbiting over a flat earth at 3000 miles, fits the current path of the sun with a sunrise and sunset and all.

Guest Jun 13, 2017

edited by
Guest
Jun 13, 2017