In triangle ABC, the angle bisector of angle BAC meets BC at D, such that AD = AB. Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees. Find angle ABD.
A
17
x x
B D C
E
"Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees." This has no bearing on the problem.
If AD = AB then angle ABD = angle ADB
So angle ABD = (180 - 17) / 2 = 81.5°
+400 
