Side lengths of a right angle triangle are 1145, 804 and 815. What size are the other two angles?
+130511 We also can use the Law of Cosines to determine the angles and side orientations.
The angle across from the shortest side =
804^2 = 815^2 + 1145^2 - 2(815)(1145) cos(theta)
cos ( theta) = [ 804^2 - 815^2 - 1145^2] / [ -2(815) (1145)]
arccos [ 804^2 - 815^2 - 1145^2] / [ -2(815) (1145)] = theta = about 44.6°
Thus.....the angle across from the second longest side = 90 - 44.6 = about 45.4°
Side lengths of a right angle triangle are 1145, 804 and 815. What size are the other two angles.
Sin(815/1145)=0.711790 [This is an assumption, since we do not know which side is the Adjacent side and which side is the Opposite.]
Asin(.711790)=45.38 degrees-one of the other two angles.
180 - [90 + 45.38]=44.62 degrees-the third angle.
+130511 We also can use the Law of Cosines to determine the angles and side orientations.
The angle across from the shortest side =
804^2 = 815^2 + 1145^2 - 2(815)(1145) cos(theta)
cos ( theta) = [ 804^2 - 815^2 - 1145^2] / [ -2(815) (1145)]
arccos [ 804^2 - 815^2 - 1145^2] / [ -2(815) (1145)] = theta = about 44.6°
Thus.....the angle across from the second longest side = 90 - 44.6 = about 45.4°
