Angle x is a third quadrant angle such that covers cos x = -2/3. What is the exact value of cos(x/2)? Enter your answer, in simplest radical form, in the box. cos(x/2) = ___

Since x lies in Q3......then x/2 will fall into Q2...so....the cosine is negative there

cos (x/2) = -√ [ (1 + cos x) / 2 ]

cos (x/2) = - √ [ ( 1 - 2/3 ) / 2 ] = - √ [ 1/6] = - √6 / 6