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In isosceles triangle $ABC$, angle $BAC$ and angle $BCA$ measure 35 degrees. What is the measure of angle $CDA$?

 

codehtml127  Jun 29, 2018
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In triangle ABC  since angles BAC and BCA  = 35°

Then angle ABC  = 180  - 35  - 35   =  180 -70 =110°

 

And because ABC  is an inscribed angle....then the major arc it intercepts, ADC,  has twice its measure = 220°

 

 So  minor arc ABC  = 360 - 220  =  140°

 

And since  CDA is an inscribed angle  intercepting this arc, it has 1/2 of its measure = 

 

(1/2) 140   =  70°

 

 

 

cool cool cool

CPhill  Jun 29, 2018

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