Angle ACB = 54. What is the size of angle CAB?
A triangle in a circle that way, always must be a right triangle, so b must be 90.
The sum of angles in a triangle are 180.
C = 54
B = 90
A + B + C = 180
A + 90 + 54 = 180
Can you solve for A?
=^._.^=
angle c = 54 and intercepts 108 degrees of arc
the remaining 72 degrees of arc of the semi-circle are intercepted by inscribed angle A
angle A = 1/2 * 72 = 36 degrees
