One of the exterior angles of an isosceles triangle is \(72\) degrees. Find the angle between the base of the triangle and the altitude drawn to one of the legs.
The sum of the exterior angles = 360
Let the other two exterior angles be equal and each measures (360 - 72) / 2 = 144
So the angle supplemental to one of these is the angle we are looking for = 180 - 144 = 36°
