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One of the exterior angles of an isosceles triangle is \(72\) degrees.  Find the angle between the base of the triangle and the altitude drawn to one of the legs.

 May 4, 2022
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The sum of the exterior angles  = 360

 

Let  the other two  exterior angles  be equal    and  each measures  (360 - 72) / 2 = 144

 

So  the  angle  supplemental to one of these is  the  angle we are looking for =  180 - 144  = 36°

 

 

cool cool cool

 May 4, 2022

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