what is pi times the reciprocal of 2/3 plus the diameter of a circle (d=9.089)
Hi Anon,
\(\pi \times \text{the reciprocal of }\dfrac{2}{3} + 9.089\\ =\dfrac{3\pi}{2}+\dfrac{9089}{1000}\\ =\dfrac{1500\pi + 9089}{1000}\)
