Hi! I have another geometry problem that I'm stuck on, can someone give me a hint or push me in the right direction?
The vertices of triangle ABC lie on the sides of equilateral triangle DEF, as shown. If CD = 3, CE = BD = 2, and angle ACB = 90, then find AE.
Here's the diagram:
Thank you in advance!
1) Find BC (use the Law of Cosines)
2) Find angle(DCB) (use either Law of Sines or Law of Cosines)
3) Find angle(ACE)
4) Find angle(CAE)
5) Find AE.