+55 Hi! I have another geometry problem that I'm stuck on, can someone give me a hint or push me in the right direction?
The vertices of triangle ABC lie on the sides of equilateral triangle DEF, as shown. If CD = 3, CE = BD = 2, and angle ACB = 90, then find AE.
Here's the diagram:
Thank you in advance!
+23252 1) Find BC (use the Law of Cosines)
2) Find angle(DCB) (use either Law of Sines or Law of Cosines)
3) Find angle(ACE)
4) Find angle(CAE)
5) Find AE.
+55 I tried what you said up until the last step, I'm probably missing ONE tiny bit but I can't seem to figure out how to do it...
+55 I didn't quite get what geno said, and I tried something different. I basically used law of cosines to find all 3 side lengths of ABC in terms of AE, then solved for it with pythagoras. It worked!
