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Hi!  I have another geometry problem that I'm stuck on, can someone give me a hint or push me in the right direction?

 

The vertices of triangle ABC lie on the sides of equilateral triangle DEF, as shown. If CD = 3, CE = BD = 2, and angle ACB = 90, then find AE.

Here's the diagram:

 

Thank you in advance!

 Jun 23, 2020
 #1
avatar+21953 
+4

1)  Find BC (use the Law of Cosines)

2)  Find angle(DCB) (use either Law of Sines or Law of Cosines)

3)  Find angle(ACE)

4)  Find angle(CAE)

5)  Find AE.

 Jun 23, 2020
 #2
avatar+110811 
+3

Nice answer Geno :)

Melody  Jun 24, 2020
 #4
avatar+55 
+1

I tried what you said up until the last step, I'm probably missing ONE tiny bit but I can't seem to figure out how to do it...

ConfuzzledKitten  Jun 26, 2020
 #3
avatar+55 
+1

Thanks!  I will try and do that! :) :)

 Jun 26, 2020
 #5
avatar+55 
+3

I didn't quite get what geno said, and I tried something different.  I basically used law of cosines to find all 3 side lengths of ABC in terms of AE, then solved for it with pythagoras.  It worked!

 Jun 26, 2020

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