+18 Once again I ask of you fine people to help me out on what kind of problem this is and what I use to solve it.
(I'm not sure if this will display the Image, if not, please copy and paste link into a seperate tab)
Once again thanks for the help and I will probably be asking more questions.
+118723 Firstly there is no N on your diagram but id doesnt matter. I think i get the drift.
<ABC=130 therrefore <FCD=130 corresponding angles on parallel lines.
<FCD=<FCE+<ECD adjacent angles
<FCE=90 therefore <ECD=40
<FEC=<ECD Alternate angles on parallel lines
therefore
<FEC=40 degrees
+118723 Firstly there is no N on your diagram but id doesnt matter. I think i get the drift.
<ABC=130 therrefore <FCD=130 corresponding angles on parallel lines.
<FCD=<FCE+<ECD adjacent angles
<FCE=90 therefore <ECD=40
<FEC=<ECD Alternate angles on parallel lines
therefore
<FEC=40 degrees
