Line $l_1$ represents the graph of $3x + 4y = -14$. Line $l_2$ passes through the point $(-5,7)$, and is perpendicular to line $l_1$. If line $l_2$ represents the graph of $y=mx +b$, then find $m+b$.
Thank you in advance.
line 1 re-arranged y = -3/4 x -14/4 slope, m, is - 3/4 perpindicular slope = - 1/m = 4/3
line 2 y = 4/3 x +b put in point given
7 = 4/3 (5) + b resulting in b = 1/3
y = 4/3 x + 1/3 m = 4/3 b = 1/3 you can add them....
1 2/3 is not correct...
Thank you though.
Please help!
+96 
