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Line $l_1$ represents the graph of $3x + 4y = -14$. Line $l_2$ passes through the point $(-5,7)$, and is perpendicular to line $l_1$. If line $l_2$ represents the graph of $y=mx +b$, then find $m+b$.

Thank you in advance.

 Mar 19, 2021
 #1
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line 1   re-arranged    y = -3/4 x -14/4       slope, m,  is   - 3/4     perpindicular slope = - 1/m  = 4/3

 

 

line 2     y = 4/3 x +b    put in point given

             7 = 4/3 (5) + b     resulting in b = 1/3

 

y = 4/3 x  + 1/3           m = 4/3    b = 1/3     you can add them....

 Mar 19, 2021
 #2
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1 2/3 is not correct...

 

Thank you though.

Immaguest  Mar 21, 2021
 #3
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Please help!

 Mar 22, 2021

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