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I don't understand how this question was solved:

16x^2=2x

x(8x-1)=0 or 1/8

 

PLS EXPLAIN

ISmellGood  Sep 10, 2017
 #1
avatar+92862 
+2

16x^2 = 2x         divide both sides by 2

 

8x^2  = x             subtract x from both sides

 

8x^2 - x  =  0      factor

 

x ( 8x - 1)  =  0

 

Setting both factors to 0   and solving

 

x  =  0         and     

 

8x - 1  = 0      add 1 to both sides

 

8x  =  1          divide both sides by 8

 

x  =  1 / 8

 

And those are the two solutions

 

 

cool cool cool

CPhill  Sep 10, 2017

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