+2448 Sumalee's school is selling tickets to a spring musical. On the first day of ticket sales the school sold 6 adult tickets and 1 student ticket for a total of $23. The school took in $106 on the second day by selling 12 adult tickets and 14 student tickets. Find the price of an adult ticket and the price of a student ticket.
+128474 Can you set up the equations, RP???
[ Hint ...let the number of adult tickets be "A" and the number of student tickets be "B" ]
EDIT...sorry A should be the cost of an adult ticket and B the cost of a student ticket
+128474 OK...good job...look at your first equation...can't we rearrange it so that we have
B = 23 - 6A ???
Knowing this...can you sub it into the second for "B" ????
+128474 OK...just simplify this
12A+14(23-6A)=106
12A + 14*23 - 14*6A = 106
12A + 322 - 84A = 106
-72A + 322 = 106 subtract 322 from each side
-72A = - 216 divide both sides by -72
A = 4 = [4$ for an adult ticket ]
Now...put 4 bacK into 23 - 6A to find the cost of a child's ticket since B = 23 - 6A
Does that make sense ???
+2448 Is it bad that I actually knew that but didn't fully process it in my head til I saw it typed out. Like it totally makes sense and I felt like I already had the answers.. lol
So B= -1
+128474 Whoops...now I made an error...!!!!
[Trying to do math in my head....never a good idea !!! ]
-72A = - 216 divide both sides by -72
A = 3 = [$3 for adult tickets]
Putting this back into 23 - 6A = 23 - 6(3) = 23 - 18 = $5 for child's ticket
But...you had the right idea...that was my stupid error...!!!
