If the sum of 9 consecutive odd integers is 1935, what is the sum of the next 9 consecutive odd integers?
(n - 10) + (n - 8) +( n - 6) + (n - 4) +( n - 2 ) +( n ) + (n + 2) +( n + 4) + (n + 6) = 1935
9n - 18 = 1935
9n = 1953
n = 217
The last odd number in the first series = 217 + 6 = 223
So....the next 9 odds are
The first term in the next series = 225
And the last term = 225 + 8(2) = 241
And the sum of this series = [ 225 + 241] * (9/20 = 2097