Peter ran at 4 m/s. Paul started at the same spot 6 sec. later and chased Peter at 7 m/s. Paul needed __ seconds to catch Peter.

APatel Jan 17, 2019

#1**+2 **

Peter gets a 4 m/s x 6 s = 24 meter head start.....when do their positions equal?

24m + 4 m/s * x s = 7 m/s * x s

24 + 4x = 7x

24 = 3x

x = 8seconds they will be at the same point ( 24 m + 4 m/s * 8 sec = 56 meters)

ElectricPavlov Jan 17, 2019