Answer it on jiskha not here

Jamie found a bag containing 56 coins. There were 4 times as many quarters as half dollars. There were 3 times as many dimes as half dollars. How many fewer half dollars were there than quarters?

Let  the  number of  half-dollars =  H

Number of  quarters  =4H

Number of dimes = 3H

So

H  + 4H  + 3H   =   56

8H  =  56

H = 56/8   =  7

Number of quarters = 4(7)  = 28

28  - 7    =  21  fewer half-dollars  than quarters