Answer pls

Solve for x:
(x-80) (x-2) = x^2-10 x

 

Expand out terms of the left hand side:
x^2-82 x+160 = x^2-10 x

 

Subtract x^2-10 x from both sides:
160-72 x = 0

 

Factor constant terms from the left hand side:
-8 (9 x-20) = 0

 

Divide both sides by -8:
9 x-20 = 0

 

Add 20 to both sides:
9 x = 20

 

Divide both sides by 9:
Answer: | x = 20/9

Do you mean\(\color {yellow}\boxed{\color{red}(x-8)(x-2)}\)? For the middle term = -10x.

If yes, \((x-8)(x-2)=x^2-10x+16\)

If no, \((x-80)(x-2)= x^2-10x -72x+160\)