-|8x+2| >-10 multiply throgh by -1 and change the direction of the inequality sign
l8x + 2l < 10 we have two equations here
Let's make this an equality and then we can figure out what the proper solution interval(s) might be
8x + 2 = 10 and 8x + 2 = -10
subtract 2 from both sides
8x = 8 8x = -12
divide both sides by 8
x = 1 x = - 12/8 → x = - 3/2
Note that the proper solution interval will lie between these two values.....thus
-3/2 < x < 1
The graph here indicates that this solution is correct :
https://www.desmos.com/calculator/ah5tytaeku