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when dividing by x-1 x+2 x-2 x-3 the polynomial p(x)=x^4+ax^3+bx^2+c+d remainder 0

 Jul 25, 2017
 #1
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Do you mean p(x)=x^4+ax^3+bx^2+cx+d ???

 

(x-1)*( x+2)*( x-2)*( x-3)=x4-4x3-1x2+16x-12

 

a=-4  b=-1   c=16   d=-12

 

laugh

 Jul 25, 2017

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