antilog of 0.3142 rounded to four decimal places

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Guest Apr 24, 2014

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With log to the base 10 this is saying log₁₀x = 0.3142, what is x?

From definition of logarithm this means x = 10^0.3142 so:

$${\mathtt{x}} = {{\mathtt{10}}}^{{\mathtt{0.314\: \!2}}} = {\mathtt{x}} = {\mathtt{2.061\: \!579\: \!086\: \!952\: \!637\: \!4}}$$

This is 2.0616 to four decimal places.

Alan Apr 25, 2014

Alan · Answer 1 · 2014-04-25T09:08:11

With log to the base 10 this is saying log₁₀x = 0.3142, what is x?

From definition of logarithm this means x = 10^0.3142 so:

$${\mathtt{x}} = {{\mathtt{10}}}^{{\mathtt{0.314\: \!2}}} = {\mathtt{x}} = {\mathtt{2.061\: \!579\: \!086\: \!952\: \!637\: \!4}}$$

This is 2.0616 to four decimal places.