Anurak has nickels, dimes, and pennies in his pocket. The coins in Anurak's pocket have a total value of 75 cents. He has three more nickels than dimes and five times as many pennies as dimes. How many coins of each type does Anurak have?
+421 This is just simple algebra: Let n,d,and p be the number of nickels, dimes and pennies Anurak has, respectively. Then the cost will be:
5n+10d+p=75.
And number of coins:
d+3=n
5d=p
So, solving we get 3 dimes, 6 nickels, and 15 pennies!
