+0  
 
0
627
3
avatar

4x^2+8x-60=0

 Feb 4, 2020

Best Answer 

 #1
avatar+304 
+1

\({-b \pm \sqrt{b^2-4ac} \over 2a} \to \frac{-8\pm \sqrt{8^2-4\cdot \:4\left(-60\right)}}{2\cdot \:4} \to\frac{-8\pm\sqrt{8^2+4\cdot \:4\cdot \:60}}{2\cdot \:4} \to\frac{-8\pm\sqrt{1024}}{2\cdot \:4}\to\frac{-8\pm\sqrt{1024}}{8}\to \frac{-8\pm32}{8}\to\frac{-40}{8}, \frac{24}{8}. \)Thus, the roots are \(\boxed{-5}, \boxed{3}.\) laugh

 Feb 4, 2020
 #1
avatar+304 
+1
Best Answer

\({-b \pm \sqrt{b^2-4ac} \over 2a} \to \frac{-8\pm \sqrt{8^2-4\cdot \:4\left(-60\right)}}{2\cdot \:4} \to\frac{-8\pm\sqrt{8^2+4\cdot \:4\cdot \:60}}{2\cdot \:4} \to\frac{-8\pm\sqrt{1024}}{2\cdot \:4}\to\frac{-8\pm\sqrt{1024}}{8}\to \frac{-8\pm32}{8}\to\frac{-40}{8}, \frac{24}{8}. \)Thus, the roots are \(\boxed{-5}, \boxed{3}.\) laugh

DragonLord Feb 4, 2020
 #2
avatar
0

Thanks

 Feb 4, 2020
 #3
avatar+304 
+1

You're welcome :D

 Feb 5, 2020

4 Online Users

avatar
avatar