+0  
 
+1
92
4
avatar+27 

Given that \((-2,3) \) is on the graph \(y = f(x)\), find a point that must be on the graph of \(y=f(2x+1)+3\). Express your answer as an ordered pair \((a,b)\) where a and b are real numbers.

 Nov 26, 2020
 #1
avatar
+3

The pair (a,b) is (5/2,-8).

 Nov 26, 2020
 #2
avatar+27 
+3

I'm sorry but this doesn't seem to be the correct answer! Thanks for trying though!

pleasehelpmequickthx  Nov 26, 2020
 #3
avatar+116126 
+3

Not great at this, but  here's  my attempt.....

 

y = f(2x + 1)  + 3

 

And we can write

 

y = 2 ( x + 1/2)  + 3

 

The "2" horizontally compresses  the  graph  by  a factor of 2

 

Thus  the  x coordinate of (-2,3)   becomes (-2 / factor , 3)  =  (-2 / 2 , 3)  =  (-1, 3)

 

The  "1/2"   shifts  the  x coordinate to the left  by  1/2  unit

Thus  (-1,3)  becomes  ( -1 - 1/2 , 3)  =  (-3/2 , 3)

 

Finally....the "3"  shifts this point up 3 unts   ...so we  have  ( -3/2 , 6)

 

cool cool cool

 Nov 26, 2020
 #4
avatar+27 
+2

Thank you very much for putting the time and effort to solve my problem!
 

(It's correct by the way!)

pleasehelpmequickthx  Nov 26, 2020

62 Online Users

avatar