The probability of drawing two red candies without replacement is 13/35 , and the probability of drawing one red candy is 2/5 .

What is the probability of drawing a second red candy, given that the first candy is red?

Guest Apr 20, 2018

#1**+2 **

Best Answer

Alright, here we go:

To draw two red candies **without** replacement is 13/35, but since drawing the first red candy is 2/5, drawing the second one, must be:

\(\frac{13}{35}\div\frac{2}{5}=\frac{13}{14}\)

GYanggg
Apr 21, 2018

#2**+2 **

The probability of drawing two red candies without replacement is 13/35 , and the probability of drawing one red candy is 2/5 .

What is the probability of drawing a second red candy, given that the first candy is red?

\(\frac{2}{5 }x=\frac{13}{35}\\ x=\frac{13}{35}\div \frac{2}{5 }\\ x=\frac{13}{35}\times \frac{5}{2 }\\ x=\frac{13}{14} \)

Melody
Apr 21, 2018