+0

# Any tricks for this?

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If $f(x) = 8x^3 - 6x^2 + 12x - 0$, what is the value of $f\left(\dfrac{3}{4}\right)$?

Aug 3, 2022

#1
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f(3/4) = 8*(3/4)^3 - 6*(3/4)^2 + 12*(3/4) - 0 = 7

Aug 3, 2022