If $f(x) = 8x^3 - 6x^2 + 12x - 0$, what is the value of $f\left(\dfrac{3}{4}\right)$?
f(3/4) = 8*(3/4)^3 - 6*(3/4)^2 + 12*(3/4) - 0 = 7
+248 
