The polynomial$$f(x) = x^3+10x^2+27x+10$$has one integer root. What is it?
my go at it, I use the integer root theorem thing and get that p/q as q=+-1, and p=+-1, +-2, +-5, +-10, now I find all possible values so
p/q=+-1, +-1/2, +-1/5, +-1/10, i plug in one of them and should get 0. I am right?
+128475 1x^3 + 10x^2 + 27x + 10
q p
It's clear that the root must be negative
You have it a little confused
Remember that p/q = all the factors of 10/ all the factors of 1
Possibilities
-1, -2. -5. -10
It can't be -1
-2 [ 1 10 27 10 ]
-2 -16 -22
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1 8 11 -12
-5 [ 1 10 27 10 ]
-5 -25 -10
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1 5 2 0
-5 is the integer root
