+0

# Anybody wanna help, thanks in advance

0
87
1

Let $a,$ $b,$ $c,$ $d,$ and $e$ be the distinct roots of the equation $x^5 + 7x^4 - 2 = 0.$ Find \begin{align*} &\frac{a^4}{(a - b)(a - c)(a - d)(a - e)} + \frac{b^4}{(b - a)(b - c)(b - d)(b - e)} \\ &\quad + \frac{c^4}{(c - a)(c - b)(c - d)(c - e)} + \frac{d^4}{(d - a)(d - b)(d - c)(d - e)} \\ &\quad + \frac{e^4}{(e - a)(e - b)(e - c)(e - d)}. \end{align*}

Dec 21, 2020

### 1+0 Answers

#1
0

The roots are

-6.99917

-0.752186

0.0188858 - 0.729393i

0.0188858 + 0.729393i

0.813591

Plugging these in, we get a value of 15.

Dec 21, 2020