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The ratio of the volumes of the water in two jugs. M and N, is 2:3 respectively. If the water in M is increased by 65%, by what percentage must the water in jug N be increased so that the volumes of the water in both jugs will be the same?

 Dec 29, 2023
 #1
avatar+126665 
+1

For convenience, let the volume of M = 20 and N =30    (M : N  = 20 : 30  = 2:3)

 

If M is is increased by 65%  it now holds   20 (1 + .65)  = 33

 

So

 

N must be increased by   ( [ 33 / 30 ]  - 1)  = 1.1 -   1 =  .1  =    10%

 

cool cool cool

 Dec 29, 2023

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