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# Anyone help

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A soccer team has five girls and four boys. (All the team members are distinguishable.) How many ways can they stand in a row for a photograph, so that at least two of the girls are standing next to each other?

I don't need the answer, I just need like a nudge to the right answer.

Dec 19, 2019

#1
+21980
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Here is my try at this Q:

There are 8 positions where the two girls can stand side by side     and you can reverse their order to have 16 possibilities of positioning 2 girls next to each other....

Now haow many ways can you choose 2 girls from the 5 on the team?     5 c 2 = 10 ways

10 x 16 = 160 ways of girl placement

there are 7 other positions to fill....how many ways can you fill them ?

7 x 6 x 5 x 4 x 3 x 2 x1 = 7!  = 5040

5040 x 160 = 806400   possibilities

Dec 19, 2019
#2
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Yeah, that's what I thought too, but it's incorect.

Guest Dec 19, 2019
#3
+21980
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Yah, I saw that in the previous post, but I thoght I would post reasoning for the answer.....maybe soemone will show us the correct way to get the correct answer (if indeed this answer is incorrect ! )

ElectricPavlov  Dec 19, 2019
#4
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Hello again! I managed to solve the problem! I first figured out how many ways to line the boys and girls and multiplied them: 5!*4!=2880.

Then, I found how many ways to line them all up. 9! = 362880. Once I found out how to line them all up, I subtracted that from the result of the boys and girls: 362880 - 2880 = 360000. And 360000's the answer!

Guest Dec 20, 2019
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+108675
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