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A soccer team has five girls and four boys. (All the team members are distinguishable.) How many ways can they stand in a row for a photograph, so that at least two of the girls are standing next to each other?

 

I don't need the answer, I just need like a nudge to the right answer.

 Dec 19, 2019
 #1
avatar+21980 
+1

Here is my try at this Q:

There are 8 positions where the two girls can stand side by side     and you can reverse their order to have 16 possibilities of positioning 2 girls next to each other....

  Now haow many ways can you choose 2 girls from the 5 on the team?     5 c 2 = 10 ways

 

10 x 16 = 160 ways of girl placement

there are 7 other positions to fill....how many ways can you fill them ?  

7 x 6 x 5 x 4 x 3 x 2 x1 = 7!  = 5040

 

5040 x 160 = 806400   possibilities    

 Dec 19, 2019
 #2
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Yeah, that's what I thought too, but it's incorect.

Guest Dec 19, 2019
 #3
avatar+21980 
+1

Yah, I saw that in the previous post, but I thoght I would post reasoning for the answer.....maybe soemone will show us the correct way to get the correct answer (if indeed this answer is incorrect ! )

ElectricPavlov  Dec 19, 2019
 #4
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Hello again! I managed to solve the problem! I first figured out how many ways to line the boys and girls and multiplied them: 5!*4!=2880. 

Then, I found how many ways to line them all up. 9! = 362880. Once I found out how to line them all up, I subtracted that from the result of the boys and girls: 362880 - 2880 = 360000. And 360000's the answer!

Guest Dec 20, 2019
 #5
avatar+108675 
0

You already asked this queston here.  

https://web2.0calc.com/questions/please-help-me_75

 

Why do you think it is ok to ask the same question twice in a short space of time?

If you want to repost you can (after a reasonable space of time) but you must always give a link to the original post.

I can see no reason here why you reposted at all.

 Dec 22, 2019
edited by Melody  Dec 22, 2019

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